A 0.5 kg weight attached to a light spring elongates it 0.981 mm. The natural frequency of the system would be approximately
A.6 cps
B.11 cps
C.16 cps
D.26 cps
E.21 cps
A.6 cps
B.11 cps
C.16 cps
D.26 cps
E.21 cps
A.Direct gear
B.First gear
C.Second gear
D.Third gear
A.Sliding and rotary pairs
B.Rolling and sliding pairs
C.Turning pair
D.Rolling pairs
E.Sliding pairs
A.One
B.Two
C.Three
D.Four
E.Six
A.Same as natural frequency of vibrations
B.Below the natural frequency of vibrations
C.Well above the natural frequency of vibrations
D.Not connected with natural frequency of vibrations
E.None of the above
A.The body A will move over the surface B irrespective of the magnitude of the force F applied on the body
B.No motion of body A on surface B is possible, irrespective of how large the magnitude of force F applied on the body may be
C.tan ? can never be equal to
D.tan ? can be equal to
E.tan ? can be equal to
A.Zero
B.One
C.Two
D.An odd number
E.An even number
A.Interference exists
B.Interference does not exist
C.Have less wear
D.Ease in transmitting variable loads
E.No lubrication needed
A.Loss of power
B.Difference between the velocities of two pulleys
C.Difference between the angular velocities of two pulleys
D.Difference between the linear speed of the rim of pulley and the belt on it
E.None of the above
A.One module
B.1.57 x module
C.1.25 x module
D.2.157/module
E.?/circular pitch