The power factor of a load of 100 kW is to be raised from 0.5 lagging to 0.9 lagging. The KVA rating of the capacitor will be
A.12.5
B.25
C.75
D.125
E.212.5
A.High current ratings
B.Higher voltages
C.High KVA
D.High kW
E.Low power factors
A.High dielectric strength
B.High inechanical strength
C.Non-inflammability
D.Low cost
E.All of the above
A.1000 kcal/kg
B.5000 kcal/kg
C.11000 kcal/kg
D.16000 kcal/kg
E.21000 kcal/kg
A.1 joule
B.1000 joules
C.1000 watt-sec
D.3600 watt-hours
E.3600,000 watt-sec
A.Increasing the conductor size and reducing the spacing between the conductors
B.Increasing the conductor size and also by increasing the spacing between the conductors
C.Reducing the conductor size and increasing the spacing between conductors
D.Reducing the conductor size as well as spacing between the conductors
E.None of the above
A.10 micro-amperes
B.25 micro-amperes
C.100 micro-amperes
D.10 milli-amperes
E.100 milli-amperes
A.1 atm
B.100 kg/cm2
C.150 kg/cm2
D.Less than 200 kg/cm2
E.More than 200 kg/cm2
A.Steam power plant
B.Diesel engine power plant
C.Gas turbine power plant
D.Nuclear power plant
E.Hydro-electric power plant
A.Self-starter
B.Cranking
C.Self-starter or cranking
D.Batteries
E.Compressed air